I talked with Benoit about this yesterday over IRC but I had no time to finish so here are some notes so that we don't forget it. The issue is what should LinSpaced(size, low, high) return when size = 1. It's not clear that this case is actually useful, but the nullary test fails currently if the randomly chosen size turns out to be 1 so something should be done about it. I see three possibilities: 1. Return [high] (as a vector). This is what Matlab does. 2. Return [low] (as a vector). This is what NumPy does (though it's not documented). 3. Leave it undefined, i.e., require that size > 1. This is what Octave does. It's also basically what we are currently doing: at the moment we are returning a vector with a NaN in it. If we go for this option, we should probably add an assert(size>1). Benoit initially thought that we should follow Matlab as that it as good a standard as there is. However, option 3 is easier to implement. In any case, we should document the decision and adapt the unit test.
This has been fixed long time ago: https://bitbucket.org/eigen/eigen/commits/fff7d72dc748a9942a44f2717aebb5e4cdb0c599 For size==1 the high value is returned.
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